Question

From a circular card sheet of radius 14cm , two circles of radius 3.5 cm and a rectangle if length 3cmand breadth of 1cm are removed( as shown in the above figure).find the area of the remaining sheet.(take pie as 22/7)​

Answer 1

Answer:

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Step-by-step explanation:

Given below as pic

1. 1 pic is the second pic and the 2 pic is the first one

Answer 2

Given:-

• Radius of the Circular card sheet is 14 cm.

• Radius of two circles is 3.5 cm.

• Length and Breadth of rectangle is 3 cm and 1 cm respectively.

To Find:-

• Remaining area of the sheet.

Solution:-

Here, Area of the Circular sheet = $\pi r^{2}$

                                                      = $\dfrac{22}{7}\times 14 \ cm\times 14 \ cm$

                                                      = 616 cm²

Now, Area of two circles = 2 × $\pi r^{2}$

                                         = 2 × $\dfrac{22}{7}\times 3.5 \ cm \times 3.5 \ cm$

                                         = 77 cm²

Now, Area of Rectangle = Length × Breadth

                                        = 3 cm × 1 cm

                                        = 3 cm²

Therefore, Area of remaining sheet = [ Area of whole sheet - ( Area of two circles + Area of rectangle ) ]

                                                           = [ 616 cm² - ( 77 cm² + 3 cm² ) ]

                                                           = [ 616 cm² - 80 cm² ]

                                                           = 581 cm²

Hence, Area of Remaining sheet is 581 cm².

Some Important Terms:-

• Perimeter of Rectangle = 2 ( Length + Breadth )

• Circumference of Circle = $2\pi r$ or $\pi d$