Question

From a circular card sheet of radius 14cm, two circles of radius 3.5cm and a rectangle of length
3cm and breadth 1cm are removed. Find the area of the remaining sheet. Take [π=22/7]
​

Answer 1

Answer:

) From a circular card sheet of radius 14 cm, two circles of radius 3.5 cm and a rectangle of length 3 cm and breadth 1cm are removed. (as shown in the adjoining figure). Find the area of the remaining sheet. (Take \pi=\frac{22}{7}π=

7

22

Solution

Radius of the circular sheet= 14cm

Area= \pi r^2=\frac{22}{7}\times14\times14cm^2πr

2

=

7

22

×14×14cm

2

=616cm^2=616cm

2

Area of 2 small circles= 2\pi r^2πr

2

=2\times\frac{22}{7}\times3.5\times3.5cm^2=2×

7

22

×3.5×3.5cm

2

=77.0cm^2=77.0cm

2

Area of the rectangle= l\times bl×b

=3\times1cm^2=3cm^2=3×1cm

2

=3cm

2

Area of the remaining sheet after removing the 2 circles and 1 rectangle

=616cm^2-\ \left(77+3\right)cm^2=616cm

2

− (77+3)cm

2

=616cm^2-\ 80cm^2=536cm^2=616cm

2

− 80cm

2

=536cm

2