from a circular card sheet of radius 16cm two circles of radius 3 cm and a rectangle of length 2.5 cm and breadth 1 cm are removed .Find the area of the remaining sheet.
Answers
Answered by
1
Area of Circular card sheet = pi * r ^2
=3.14*16*16
=803.84
Area of one circles= pi*r^2
=3.14*3*3
=28.26
Area of two circles= 28.26*2=56.52
Area of Rectangle=l*b = 2.5*1 = 2.5
Area of remaining sheet=Area of Circular card sheet -
Area of two circles - Area of Rectangle.
=803.84-56.52-2.5
=744.82
=3.14*16*16
=803.84
Area of one circles= pi*r^2
=3.14*3*3
=28.26
Area of two circles= 28.26*2=56.52
Area of Rectangle=l*b = 2.5*1 = 2.5
Area of remaining sheet=Area of Circular card sheet -
Area of two circles - Area of Rectangle.
=803.84-56.52-2.5
=744.82
Answered by
0
Answer:
Area of an circular sheet = πR²
= 22/7 x 16 cm x 16 cm
= 22/7 x 256 cm²
= 5632 /7 cm ²
= 804.59 cm ²
Area of inner circle = π²
= 22/7 x 3 x 3
= 198/7 cm ²
=28.28 cm²
Area of two inner circles = 28.28 x 2
= 56.56 cm ²
Area of rectangle= l x b
= 2.5 cm x 1 cm
= 2.5 cm²
Remaining area of circular sheet = Area of circular sheet - ( area of inner circles + area of rectangle)
= 804.56 cm ² - (56.56 cm ² + 2.5 cm ²)
= 804.56 cm ² - 59.06 cm ²
= 745.5 cm ² Ans.
Similar questions