Question

From a circular disc of diameter 8 cm, a square of side 1.5 cm is removed. Find thearea of the remaining poriton of the disc. (Use t=3.14)
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. solve the question step by step
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Answer 1

Answer:

simply get the difference of the areas of the two figure

Answer 2

$\huge† \huge \bold{\: \pmb {\red{Question}} }$

• From a circular disc of diameter 8 cm, a square of side 1.5 cm is removed. Find thearea of the remaining poriton of the disc. (Use t=3.14)

$\huge† \huge \bold{\: \pmb {\red{Answer}} }$

Our figure will look like(in attachment)

Now,

• Area remaining = Area of bigger circle - Area of smaller circle

Let's find both these areas.

Area of bigger circle

• Radius = r = 4 cm

$\sf \: Area = πr² \\ \\ \sf \: = 3.14 × (4)² \\ \\ \sf \: = 3.14 \times 16 \\ \\ \sf \: = \frac{314}{100} \times 16 \\ \\ \sf = \frac{5024}{100} \\ \\ \sf \: = 50.24 \: cm²$

Area of smaller circle

• Radius = r = 3 cm

$\sf \: Area = πr² \\ \\ \sf = 3.14 × (3)² \\ \\ \sf \: = 3.14 × 9 \\ \\ \sf \: = \frac{314}{100} \times 9 \\ \\ \sf = \frac{2826}{100} \\ \\ \sf= 28.26 \: cm²$

Area remaining Area of bigger circle - Area of smaller circle

$\sf \: Area \: remaining = 50.24 - 28.26 \\ \\ \sf \: = \frac{5024}{100} - \frac{2826}{100} \\ \\ \sf = \frac{5024-2826}{100} \\ \\ \sf = \frac{2198}{100} \\ \\ = \boxed{ \red{ \sf 21.98 \: {cm}^{2} }}$

$\therefore \sf Area \: of \: remaining \: sheet \: is \: \bold{21.98 \: cm²}$

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