From a circular disc of radius 28cm, two circles of radius 7/2cm each, a triangle of base 3cm and height 2cm, a rectangle of length 4cm and breadth 3cm are cut out. Find the area of remaining disc.
Answers
Step-by-step explanation:
Radius of circular sheet(R)=14cm and Radius of smaller circle(r)=3.5cm
Length of rectangle(l)=3cm and breadth of rectangle(b)=1cm
According to question,
Area of remaining sheet=Area of circular sheet−[Area of two smaller circle+Area of rectangle]
=πR
2
−[2(πr
2
)+(l×b)]
=
7
22
×14×14−[(2×
7
22
×3.5×3.5)−(3×1)]
=22×14×2−[44×0.5×3.5+3]
=616−80
=536cm
2
Therefore the area of remaining sheet is 536cm
2
.
Radius of circular sheet(R)=14cm and Radius of smaller circle(r)=3.5cm
Length of rectangle(l)=3cm and breadth of rectangle(b)=1cm
According to question,
Area of remaining sheet=Area of circular sheet−[Area of two smaller circle+Area of rectangle]
=πR
2
−[2(πr
2
)+(l×b)]
=
7
22
×14×14−[(2×
7
22
×3.5×3.5)−(3×1)]
=22×14×2−[44×0.5×3.5+3]
=616−80
=536cm
2
Therefore the area of remaining sheet is 536cm
2