Question

From a circular
radius 3.5 cm and
ircular card sheet of radius 14 cm, two circles of
25 cm and a rectangle of length 3 cm and breadth
re removed (as shown in the adjoining figure).
God the area of the remaining sheet.​

Answer 1

Step-by-step explanation:

length length of rectangle is equal to 3 centimetre and breadth of rectangle is equal to 1 centimetre

according to question

area of remaining sheet is equal to area of circular sheet -(area of two smaller circle plus area of rectangle.

πr square - (2(πr square)+ ( l x b).

22/7*14*14-( 2*22/7*3.5*3.5)- 3*1).

22*14*2-(44*.5*3.5+3).

616-80

= 536 m square

.

Answer 2

$\large{\bf{\red{\underline{\underline{AnsWer}}}}}$

Area of outer circle =$\pi {r}^{2} \\ = \frac{22}{7} \times 14 \times 14 \\ = 22 \times 28 = 616 cm²</p><p>⠀⠀⠀⠀</p><p>\\ \\ area \: of \: inner \: circle \: = 2 \times \pi {r}^{2} \\ \: = \: 2 \times \frac{22}{7} \times 35 \times 35 \\ = 22 \times 3.5 \\ = 77 {cm}^{2} \\ \\ </p><p>area \: of \: rectangle = \: l \times b \\ area</p><p> \: of \: whole \: circle \: -</p><p> \: ( \: area </p><p>\: of \: the</p><p> \: both \: circles \: </p><p>+ </p><p>\: area \: of</p><p> \: rectangle</p><p> \: ) \: = \: area </p><p>\: of</p><p> \: remaing \: sheet. \\ = 616 \: - \: ( \: 77 + 3) \\</p><p> = 616 - 80 = </p><p> {536cm}^{2} ....$