Question

From a circular sheet of a radius 5 cm, a circle of radius 3 cm is removed. Find the area of the remaining sheet

Answer 1

this is the solution

Answer 2

$\mathfrak{\huge{Answer:}}$

$\mathbb{GIVEN}$

Radius of the bigger circle = 5 cm

Radius of the smaller circle = 3 cm

$\mathbb{TO\:FIND}$

The Area left after the circle of radius 3 cm is cut from the circle of radius 5 cm.

$\mathbb{METHOD}$

Generally, we use a simple method for these types of questions. We simply subtract the area of the smaller figure from the bigger figure.

Here, the bigger figure = Circle (○) with radius 5 cm

Smaller figure = Circle (○) with radius 3 cm

Area of the bigger figure ( the bigger circle in this case ) = $\sf{\pi R^{2}}$

Area of smaller figure ( the smaller circle in this case ) = $\sf{\pi r^{2}}$

Area of the left over region ( most probably a circular region ) = $\sf{\pi R^{2}}$ - $\sf{\pi r^{2}}$

=》 Area of the let over region = $\sf{\pi (R^{2} - r^{2})}$

=》 Area of the let over region = $\sf{\pi (5^{2} - 3^{2})}$

=》 Area of the left over region = $\sf{ 16 \pi}$

=》 Area of the left over region = 50.265 $\sf{cm^{2}}$