Question

From a circular sheet of a radius 6 CM a circle of radius 4 centimetre is removed find the area of a remaining sheet

Answer 1

$= > area \: of \: big \: circle = \pi \: {r}^{2}$
$= > a \: \: = \frac{22}{7} \times 6 \times 6$

$= > \: a \: \: = 113.14 \: {cm}^{2}$
Now,

$= > area \: of \: small \: circle = \pi \: {r}^{2}$

$= > a \: \: = \frac{22}{7} \times 4 \times 4$

$= > \: a \: \: = 50.28 \: {cm}^{2}$

Again,

Area of remaining part = Area of big circle-Area of Small circle

=> Area of remaining part = (113.14-50.28) cm^2

=> Area of remaining part = 62.86 cm^2


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