Question

From a circular sheet of a radius of 5 cm, a circle of radius 3 cm is removed. Find the area of the remaining sheet.

Answer 1

Given :

• A circular sheet of radius 3 cm is removed from a circular sheet of radius 5 cm

To find :

• Area of the remaining part

Solution :

According to the question,

Area of remaining sheet = Area of circular sheet of radius 5 cm - area of circular sheet with radius of 3 cm

= Π(5)² - Π(3)²

= 25Π - 9Π

= 16Π

•°• Required area = 16Π

____________________________

More to know :

• Area of circle = Π(radius of the circle)²
• Circumference of the circle = 2Π(radius)

Answer 2

Gɪᴠᴇɴ :-

• Radius (R) of sheet = 5cm
• Radius (r) of circle = 3 cm

ᴛᴏ ғɪɴᴅ :-

• Area of remaining sheet

sᴏʟᴜᴛɪᴏɴ :-

Let the radius of circular sheet be R and radius of circle removed be r

then,

We know that,

• Area of Circle = πr²

Hence,

➠ Area of Remaining sheet = πR² - πr²

➠ πR² - πr²

➠ π(R² - r²)

➠ π(R + r) (R - r)

➠ π(5 + 3)(5 - 3)

➠ π(8)(2)

➠ 16π

➠ 22/7 × 16

➠ 352/16

➠ 50.28 cm²

Hence,

• Area of remaining sheet = 50.28cm²