Question

From a circular sheet of diameter 42cm, two circles of diameter 7cm and a triangle of base 4cm and height
6cm are removed. Find the area of the remaining sheet.
S​

Answer 1

Answer:

Area of the whole sheet=$\pi r^{2}$

=$\frac{22}{7} *21*21\\=22*3*21$

=1386sqcm

area of 2 circles=

$\pi r^{2} \\=3.14*3.5*3.5=3.14*12.25\\=38.465*2\\=76.93sq.cm$

area of triangle=b*h*1/2

=4*6*1/2

=4*3=12sqcm

area of 2 circles + area of triangle=

76.93+12=88.93sqcm

area of remaining sheet=1386-88.93=

1297.07sqcm

Step-by-step explanation: