From a circular sheet of radius 14 cm, two circles of radius 3.5 cm and a rectangle of length 3 cm and breadth 1 cm are removed. Find area of remaining sheet. (Taking π =22/7)
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Radius of the circular sheet= 14cm
Area= \pi r^2=\frac{22}{7}\times14\times14cm^2
=616cm^2
Area of 2 small circles= 2\pi r^2
=2\times\frac{22}{7}\times3.5\times3.5cm^2
=77.0cm^2
Area of the rectangle= l\times b
=3\times1cm^2=3cm^2
Area of the remaining sheet after removing the 2 circles and 1 rectangle
=616cm^2-\ \left(77+3\right)cm^2
=616cm^2-\ 80cm^2=536cm^2
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