Question

from a circular sheet of radius 14cm two circles of radius 3.5and a rectangle of length 3cm and breadth 1cm are removed find the area of the remaining sheet
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Answer 1

Answer:

step by step explaintion

Total area of circular sheet =2πr^2

where r=14cm (given)

2×22/7×14×14

44×28

1232cm^2

now, area of two smaller circles

radius = 3.5cm

area = 2(2πr^2)

2×2×22/7×3.5×3.5

44×3.5=154cm^2

now, area of rectangle

length=3cm and breadth=1cm

area=length×breadth

3×1=3cm^2

for the area, adding the areas of rectangle and two circles

= 154+3=157cm^2

for the remaining area in circular sheet

substracting the area rectangle and two circles from larger circle

therefore 1232-157=1075cm^2

hence the remaining area in circular sheet= 1075cm^2

hope it helps

Answer 2

$\large{\bf{\green{\underline{\underline{♧AnsWer♧}}}}}$

Area of outer circle =$\pi {r}^{2} \\ = \frac{22}{7} \times 14 \times 14 \\ = 22 \times 28 = 616 cm²</p><p>⠀⠀⠀⠀</p><p>\\ \\ area \: of \: inner \: circle \: = 2 \times \pi {r}^{2} \\ \: = \: 2 \times \frac{22}{7} \times 35 \times 35 \\ = 22 \times 3.5 \\ = 77 {cm}^{2} \\ \\ </p><p>area \: of \: rectangle = \: l \times b \\ area</p><p> \: of \: whole \: circle \: -</p><p> \: ( \: area </p><p>\: of \: the</p><p> \: both \: circles \: </p><p>+ </p><p>\: area \: of</p><p> \: rectangle</p><p> \: ) \: = \: area </p><p>\: of</p><p> \: remaing \: sheet. \\ = 616 \: - \: ( \: 77 + 3) \\</p><p> = 616 - 80 = </p><p> {536cm}^{2} ....$