From a circular sheet of radius 21 cm, 5 circles of radius 3.5 cm, a rectangle of length 4 cm and breadth 3 cm, and a square of side 1 cm are removed. Find the area of the remaining sheet.
Answers
Step-by-step explanation:
"Radius of circular sheet (R) = 14 cm and radius of smaller circle (r) = 3.5 cm
Length of rectangle (l) = 3 cm and breadth of rectangle (b) = 1 cm
Area of the remaining sheet = Area of circular sheet – (Area of two smaller circle + Area of rectangle)
= πR2 – [2πr 2 + (length × Breadth)]
= 22/7 ×14 cm × 14 cm - [2 × 22/7 × 3.5 cm × 3.5 cm + (3 cm × 1 cm)]
= 22 × 2 cm × 14 cm - [44/7 × 3.5 cm × 3.5 cm + 3 cm]
= 616 cm2 - (77 + 3) cm2
= (616 - 80) cm2
= 536 cm2
Therefore, the area of the remaining sheet is 536 cm2"
Answer:
Radius of circular sheet(R)=14cm and Radius of smaller circle(r)=3.5cm.
Length of rectangle(l)=3cm and breadth of rectangle(b)=1cm.
According to question,
Area of remaining sheet=Area of circular sheet−[Area of two smaller circle+Area of rectangle].
= πR^2 − [2(πr^2 )+(l×b)].
= 7/22 × 14×14− [(2 × 7/22 × 3.5×3.5) − (3×1)].
= 22×14×2−[44×0.5×3.5+3].
= 616 − 80.
= 536cm^2
Therefore the area of remaining sheet is 536cm
Therefore the area of remaining sheet is 536cm 2.