Question

From a circular sheet of radius 4 cm, a circle of radius 3 cm is removed. Find the area of the remaining sheet.

Answer 1

R = 4 cm

Area of circle = πR²

A1 = 16πcm²

Now a circle of 3cm is removed , area of that circle will be

A2 = π×9 = 9πcm²

Now , area of remaining circle = A1-A2
=( 16-9)π cm²

= 7 π cm²

Putting value of π = 22/7

= 7×22/7 = 22 cm²

Answer 2

Given:

• Radius of the circular sheet = 4 cm
• Radius of the circle removed = 3 cm

To Find:

Area of the remaining circle.

Solution:

Radius of outer circle = 4 cm

Radius of inner circle = 3 cm

According to the given information,

Area of the outer circle = $\pi (4^{2} )= 16\pi$

Area of the inner circle = $\pi (3^{2})=9\pi$

Now,

Remaining area = $16\pi -9\pi = 7\pi = 7 \times \frac{22}{7} = 22m^{2}$

Therefore $:\implies \boxed {Remaining \: area \: of \: the \: sheet \: is \: 22m^{2} }$