From a circular sheet of radius 4 cm ,a circle of radius 3 cm is removed. find the area of the remaining sheet. ( take π = 3.14)
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Answered by
1
Answer:
The area of the circular sheet with 4cm radius is,
A=πr
2
=16π
The area of the circular sheet with 3cm radius is,
A=πr
2
=9π
Since the circle with radius 3cm is removed, then the remaining area is,
A=16π−9π
=7π
=7×3.14
=21.98cm
2
Answered by
2
Answer:
Radius of circular sheet (r₁) = 4 cm
Radius of removed circle (r₂) = 3 cm
Area of remaining sheet = Area of circular sheet – Area of removed circle = πr₁2 - πr₂2
= π (r₁2 - r₂2)
= 3.14 (42 - 32) cm2
= 3.14 (16 - 9) cm2
= 3.14 × 7 cm2
= 21.98 cm2
Thus, the area of the remaining sheet is 21.98 cm2.
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