Math, asked by xxbadmaash01x, 17 days ago

From a circular sheet of radius 4 cm, a circle of radius 3 cm is removed. Find the area of the remaining sheet. (Take π = 3.14)​

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Answers

Answered by Mìßßy
1

Answer:

Radius of circular sheet (r₁) = 4 cm

Radius of circular sheet (r₁) = 4 cmRadius of removed circle (r₂) = 3 cm

Radius of circular sheet (r₁) = 4 cmRadius of removed circle (r₂) = 3 cmArea of remaining sheet = Area of circular sheet – Area of removed circle = πr₁2 - πr₂2

Radius of circular sheet (r₁) = 4 cmRadius of removed circle (r₂) = 3 cmArea of remaining sheet = Area of circular sheet – Area of removed circle = πr₁2 - πr₂2= π (r₁2 - r₂2)

Radius of circular sheet (r₁) = 4 cmRadius of removed circle (r₂) = 3 cmArea of remaining sheet = Area of circular sheet – Area of removed circle = πr₁2 - πr₂2= π (r₁2 - r₂2)= 3.14 (42 - 32) cm2

Radius of circular sheet (r₁) = 4 cmRadius of removed circle (r₂) = 3 cmArea of remaining sheet = Area of circular sheet – Area of removed circle = πr₁2 - πr₂2= π (r₁2 - r₂2)= 3.14 (42 - 32) cm2 = 3.14 (16 - 9) cm2

Radius of circular sheet (r₁) = 4 cmRadius of removed circle (r₂) = 3 cmArea of remaining sheet = Area of circular sheet – Area of removed circle = πr₁2 - πr₂2= π (r₁2 - r₂2)= 3.14 (42 - 32) cm2 = 3.14 (16 - 9) cm2 = 3.14 × 7 cm2

Radius of circular sheet (r₁) = 4 cmRadius of removed circle (r₂) = 3 cmArea of remaining sheet = Area of circular sheet – Area of removed circle = πr₁2 - πr₂2= π (r₁2 - r₂2)= 3.14 (42 - 32) cm2 = 3.14 (16 - 9) cm2 = 3.14 × 7 cm2 = 21.98 cm2

Radius of circular sheet (r₁) = 4 cmRadius of removed circle (r₂) = 3 cmArea of remaining sheet = Area of circular sheet – Area of removed circle = πr₁2 - πr₂2= π (r₁2 - r₂2)= 3.14 (42 - 32) cm2 = 3.14 (16 - 9) cm2 = 3.14 × 7 cm2 = 21.98 cm2Thus, the area of the remaining sheet is 21.98 cm2.

Find the area of the remaining sheet. (Take π = 3.14) Thus, the area of the remaining sheet is 21.98 cm2.

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Answered by pragyarani2801
0

Answer:

This relationship, known as Faraday's law of induction (to distinguish it from his laws of electrolysis), states that the magnitude of the emf induced in a circuit is proportional to the rate of change of the magnetic flux that cuts across the circuit.

This relationship, known as Faraday's law of induction (to distinguish it from his laws of electrolysis), states that the magnitude of the emf induced in a circuit is proportional to the rate of change of the magnetic flux that cuts across the circuit.

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