from a circular sheet of radius 4cm,a circle of 3cm is removed.Find the area of the remaining sheet.
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5
area of circle=π®^2
=22/7×4×4
=50.28
area of circle
=22/7×3×3
=28.28
50.28-28.28=22 cm^2
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Answered by
3
Answer :
Given :
Radius of circular sheet = 4 cm
Radius of the circle cut from the circular sheet = 3cm
To find :
Area of the remaining sheet
Solution :
Let area of the bigger circle be x
Let area of the smaller circle be y
area of bigger circle = πr^2
x = 22÷7 X 4 X 4
x = 22 ÷ 7 X 16
x = 50.285 cm ^2
area of smaller circle = πr^2
y = 22÷7 X 3 X 3
y = 22 ÷ 7 X 9
y = 28.285 cm ^2
area of the remaining sheet = area of bigger circle - area of smaller circle
= x - y
= 50.285 - 28.285
= 22 cm ^2
Hope this helps you .
Please mark it as brainliest.
Given :
Radius of circular sheet = 4 cm
Radius of the circle cut from the circular sheet = 3cm
To find :
Area of the remaining sheet
Solution :
Let area of the bigger circle be x
Let area of the smaller circle be y
area of bigger circle = πr^2
x = 22÷7 X 4 X 4
x = 22 ÷ 7 X 16
x = 50.285 cm ^2
area of smaller circle = πr^2
y = 22÷7 X 3 X 3
y = 22 ÷ 7 X 9
y = 28.285 cm ^2
area of the remaining sheet = area of bigger circle - area of smaller circle
= x - y
= 50.285 - 28.285
= 22 cm ^2
Hope this helps you .
Please mark it as brainliest.
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