Question

From a circular sheet of radius 4cm, a circle of radius 3cm is removed.

Find the area of the remaining sheet (Take π = 3.14).​

Answer 1

Answer:

The area of the circular sheet with 4cm radius is,

A=πr

2

=16π

The area of the circular sheet with 3cm radius is,

A=πr

2

=9π

Since the circle with radius 3cm is removed, then the remaining area is,

A=16π−9π

=7π

=7×3.14

=21.98cm

2

Answer 2

Answer:

Area of the remaining sheet is 22cm²

Explanation:

Area if the remaining sheet : $\sf C_2 - C_1$

Where,

• $\sf C_2$ denotes the area of outer circle.
• $\sf C_1$ denotes the area of inner circle.

Area of $\sf C_2$ is given by : πr²

Where, r is the radius of 4cm and the taking ‘π’ as 3.14

So, the area is

→ 3.14 × 4²

→ 3.14 × 16

→ 50.24cm²

And also,

Area of $\sf C_1$ : πr²

Where, ‘r’ is 3cm.

So, the area is

→ 3.14 × 3²

→ 3.14 × 9

→ 28.26

Therefore, area of the remaining sheet is :

→ 50.24 - 28.26

→ 21.98

→ 22cm² (approx.)