Question

From a circular sheet of radius 4cm , a circle of radius of 3cm is removed find the area of remaining sheet

Answer 1

$= > area \: of \: big \: circle = \pi \: {r}^{2}$
$= > a \: \: = \frac{22}{7} \times 4 \times 4$

$= > \: a \: \: = 50.28 \: {cm}^{2}$

Now,

$= > area \: of \: small \: = \pi \: {r}^{2}$

$= > \: a \: \: = \frac{22}{7} \times 3 \times 3$

$= > a \: \: = 28.28 \: {cm}^{2}$

Again,

Area of remaining part = Area of big circle-Area of Small circle.

=>Area of remaining part = (50.28-28.28)cm^2

=> Area of remaining part = 22 cm^2



Be Brainly

Answer 2

Question

From a circular sheet of radius 4cm , a circle of radius of 3cm is removed find the area of remaining sheet

Answer

Radius of circular sheet (R) = 4cm

Radius of circule which is removed = 3cm

Area of remaining sheet = Area of circular sheet - Area of circle which is removed.

= π R² - πr²

= π ( R² - r² )

= 314 ( 14 )² - (3)²)

= 314 ( 16 - 9 )

= 3.14 (7)

= 3.14 × 7

= 21.98cm²