From a city population, the probability of selecting i) a male or a smoker is 7/10, ii) a male smoker is 2/5, and iii) a male, if a smoker is already selected is 2/3. Find the probability of selecting i) a non-smoker, ii) a male, and iii) a smoker, if a male is first selected.
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Step-by-step explanation:
Given From a city population, the probability of selecting i) a male or a smoker is 7/10, ii) a male smoker is 2/5, and iii) a male, if a smoker is already selected is 2/3. Find the probability of selecting i) a non-smoker, ii) a male, and iii) a smoker, if a male is first selected.
- Let the male be m and the smoker selected be s
- Now P (M U S) = 7/10, P(M Ո S) = 2/5, P (M/S) = 2/3
- Now probability of selecting a smoker is P(S) = P(M ) / P(M / S)
- = 2/5 / 2/3
- = 2/5 x 3/2
- = 3/5
- Probability of selecting a male will be
- P(M) = P(M U S) + P (M Ո S) – P(S)
- = 7/10 + 2/5 – 3/5
- = 7 + 4 – 6 / 10
- = ½
- Now probability of selecting a smoker (male) will be P (S / M)
- P (S / M) = P (M Ո S) / P(M)
- = 2/5 / ½
- = 2/5 x 2
- = 4/5
Reference link will be
https://brainly.in/question/27741612
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4/5 will be the correct answer
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