Question

From a cliff of 49m, a man drops a stone. One second later he throws another stone. They both hit the ground at the same time. Find out the speed with which he threw the second stone.


Please answer fast.
I'll mark him/her as brainliest plzzzz answer fast

Answer 1

first stone -
s = ut+1/2gt
49=1/2x9.8 x t sq
98/9.8=t sq
t=√10 seconds
second stone-
t=(√10-1) seconds
49=u x (√10-1)+1/2x9.8x(√10-1) whole square
since √10-1=3.16-1=2.16 seconds
49= u x 2.16+1/2x9.8x(2.16) whole square
49=u x 2.16+22.8164
26.1385=u x2.16
u=12.101m/s
hope this helps ☺️