Question

From a cliff of 49m high, a man drops a stone. One second later, he throws another stone. They both hit the ground at the same time. Find out the speed with which he threw the second stone.PLEASE!! (Use equations of motion etc. and show the working!)............

Answer 1

Relative Acceleration =0
Relative velocity =v
S=1/2gt2,
So t=root over 10s
V=49 divided by root over 10 m/s