Question

From a container having pure milk, 20% is replaced by water and the process is repeated thrice. At the end of the third operation , the milk is

Answer 1

Answer:

40% milk is left as if this process is repeated thrice 60% water will be added instead of milk

Step-by-step explanation:

Answer 2

Answer:

Given,

Let pure  milk = 100 liter  

water is replaced  in 20% in per process  = 20% of 100

=>20 liter  

Now

Quantity of Milk reduced to,

= X× [1 - (Y/X)]n

here

X = Initial quantity of milk.

Y = Replaced water in per process.

n = No. of process repeated.

= 100 × [1- (20/100)]3

= (100× 64)/(125)

= 51.2 L.

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@GauravSaxena01