From a cord of 16m length ,two pieces of length 10/3 and 12/5 m are cut off . Find the length of remaining
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Concept:
The remaining of any quantity in mathematics is founded by subtraction of total used from the initial total amount.
Given:
Given that, From a cord of 16m length ,two pieces of length 10/3 and 12/5 m are cut off.
Find:
The length of remaining the cord.
Solution:
Total length of a cord is 16 m.
The cut off lengths are 10/3 m and 12/5 m respectively.
The total length which is cut off
= 10/3 + 12/5
= (10*5+12*3)/15, since LCM of 3,5 = 15
= (50+36)/15
= 86/15
= 5.73 m (approximately)
Hence the length of the remaining cord after cutting off 10/3 m and 12/5 m from 16 m cord is given by 5.73 m approximately.
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