Question

from a cube of side 8m a square hole of side 3m is hollowed from end to end. find the volume of remaining solid​

Answer 1

hey mate here is your answer:

volume of remaining solid(v)=volume of cube-volume of square

$v = side {}^{3} - side {}^{3}$

$v = (8) \times (8) \times (8) - (3) \times (3) \times (3)$

$v =( 512 - 27)m {}^{3}$

$v = 485m {}^{3}$

Answer 2

The volume of remaining solid​ is 440 m³.

Step-by-step explanation:

The volume of a cube is

$V=a^3$

where, a is side length.

The volume of a cuboid is

$V=l\times b \times h$

where, l is length, b is breadth and h is height.

It is given that side length of a cube is 8m. So, the volume of cube is

$V_1=(8)^3=512$

A square hole of side 3m is hollowed from end to end. The shape of hole is a cuboid with length 8m, width 3 m and height 3 m. So, the volume of cuboid is

$V_2=8\times 3\times 3=72$

The volume of remaining solid​ is

$V=V_1-V_2=512-72=440$

Therefore, the volume of remaining solid​ is 440 m³.

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