Math, asked by nikita783942, 11 months ago

from a cubic polynomial whose zeroes are 3,2 and - 1 hence find sum of its zeros, sum of the product taken two at the time, product of its zeroes​

Answers

Answered by chauhan091976
3

Let @#$the zeroes

Then equation is

X^3-(@+#+$)X^2+(@#+@$+#$)X-@#$

=x^3-(2+3-1)X^2+[2(3)+3(-1)+2(- 1)]x-(2)(3)(-1)

=x^3-4x^2+[6-3-2]x+6

=x^3-4x^2+x+6

It Is the equation formed

@+#+$=4

@#+#$+@$=1

@#$=-6

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