from a cubic polynomial whose zeroes are 3,2 and - 1 hence find sum of its zeros, sum of the product taken two at the time, product of its zeroes
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Let @#$the zeroes
Then equation is
X^3-(@+#+$)X^2+(@#+@$+#$)X-@#$
=x^3-(2+3-1)X^2+[2(3)+3(-1)+2(- 1)]x-(2)(3)(-1)
=x^3-4x^2+[6-3-2]x+6
=x^3-4x^2+x+6
It Is the equation formed
@+#+$=4
@#+#$+@$=1
@#$=-6
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