Math, asked by Ashwin1701Volt, 1 month ago

From a cuboidal solid metal block of dimensions (15)(10)(5)cm,a cylindrical hole of diameter 7cm, is drilled out. find the surface area of the block.

Answers

Answered by Anonymous

Answer:

Breadth of the cuboidal solid metallic block(b) = 10 cm. Height of the cuboidal solid metallic block = height of the cylinder (h) = 5 cm. = 583 cm². Hence, the Surface area of the remaining block = 583 cm².

Answered by Simran200837

Answer:

Breadth of the cuboidal solid metallic block(b) = 10 cm. Height of the cuboidal solid metallic block = height of the cylinder (h) = 5 cm. = 583 cm². Hence, the Surface area of the remaining block = 583 cm².

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From a cuboidal solid metal block of dimensions (15)(10)(5)cm,a cylindrical hole of diameter 7cm, is drilled out. find the surface area of the block.​

Answers

Breadth of the cuboidal solid metallic block(b) = 10 cm. Height of the cuboidal solid metallic block = height of the cylinder (h) = 5 cm. = 583 cm². Hence, the Surface area of the remaining block = 583 cm².

From a cuboidal solid metal block of dimensions (15)(10)(5)cm,a cylindrical hole of diameter 7cm, is drilled out. find the surface area of the block.