From a cuboidal solid metal block of dimensions (15)(10)(5)cm,a cylindrical hole of diameter 7cm, is drilled out. find the surface area of the block.
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Answer:
Breadth of the cuboidal solid metallic block(b) = 10 cm. Height of the cuboidal solid metallic block = height of the cylinder (h) = 5 cm. = 583 cm². Hence, the Surface area of the remaining block = 583 cm².
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3
Answer:
Breadth of the cuboidal solid metallic block(b) = 10 cm. Height of the cuboidal solid metallic block = height of the cylinder (h) = 5 cm. = 583 cm². Hence, the Surface area of the remaining block = 583 cm².
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