Question

from a cuboidal wooden block whose length, breadth and height are 15 cm, 10cm and 5 cm respectively. A cylindrical hole of diameter 7 cm is drilled out along the height of cuboid. find the surface area of remaining solid.​

Answer 1

Step-by-step explanation:

surface area of whole block

=2(lb+lh+bh)

=2(15*10+15*5+10*5)

=2(150+75+50)

=2*275

=550cm sq

s.a. of cylinder=2πr(h+r)

r=3.5cm

s.a.=2*π*3.5(5+3.5)

s.a.=187 cm sq

s.a of remaining solid=550-187=363cm sq

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