Question

from a cyclic quadrilateral BOD =100° THEN FIND THE ANGLES OF BAD and BCD

Answer 1

Answer:

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Step-by-step explanation:

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As ABCD is a cyclic quadrilateral

then sum of opposite angles ( i.e. BCD + BAD = 180 ) as BAD = 80

AS BAD is a triangle

ABD + BAD + ADB = 180

70 + 80 + ADB = 180

ADB = 180 - 150

ADB = 30