Math, asked by soodkanishk8601, 1 year ago

From a cylinder of radius r a cylinder of radius r/2 is removed as shown

Answers

Answered by gauravarduino
1

Step-by-step explanation:

In all the above cases Bsurface=μ0i2πR Inside the hollow cylinder: Magnetic field inside the hollow cylinder is zero. Inside the solid cylinder: Current ...

Answered by Anonymous
0

Answer:

Current density: ρ=πR2−π(R/2)21⇒ρ=3πR24I

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