From a dam, water is pouring down at the rate of 150 kg/s, on the blades of a turbine. If a ball dropped from the same dam takes 2√5 s to hit the turbine, then the power delivered to the turbine is approximately equal to (Take g = 10 m/s²)
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Answered by
24
From the given question we can say that the power is here to be find
And N=dalta mgh
we don't know about the height so in order to find height formulla is
h = gt²/2 = 10*( 2√5)²/2 as we know g= 10 and time = 2√5
so height = 100 meter
and
N=Δmgh
by putting the values in the equation
N= 150*10*100 = 1.5 * 10^5 W
So the power will be 1.5*10^5 W.
And N=dalta mgh
we don't know about the height so in order to find height formulla is
h = gt²/2 = 10*( 2√5)²/2 as we know g= 10 and time = 2√5
so height = 100 meter
and
N=Δmgh
by putting the values in the equation
N= 150*10*100 = 1.5 * 10^5 W
So the power will be 1.5*10^5 W.
Answered by
1
Answer:
the answer is 1.5*10 power 5 w.
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