Question

From a dam,water is pouring down at the rate of 150 kg/s, on the blades of a turbine.if a ball dropped from the same dam takes 2✓5 s to hit the turbine,then the power delivered to the turbine is approximately equal to

Answer 1

Hi friend,

Height of the dam=

S= ut + 1/2 g t²

Here initial velocity (u) = 0.

S= 0.5 × 10×(2√5)²

S= 100m.

power= total change inpotential energy

= ∆mgh
= 150×10×100

= 150000watt = 150kw.

Hope this helped you a little!!!

Answer 2

height of the dam s = 1/2 g t^2
s = 1/2 × 10×(2 sqrt(5))^2 = 100m.

Power in the water striking the turbines = m g h / time
P = 150 kg/s* 10 m/s^2* 100 m
= 150 kW