Math, asked by jijimathew80, 9 months ago

From a deck of cards, 10 cards are picked at random and shuffled. The cards are as follows: 6, 5, 3, 9, 7, 6, 4, 2, 8, 2 Find the probability of picking a card having value more than 5 and find the probability of picking a card with an even number on it.

Answers

Answered by TPS
156

The 10 selected cards are:  6, 5, 3, 9, 7, 6, 4, 2, 8, 2

cards having value more than 5 = 6, 9, 7, 6, 8

total cards having value more than 5 = 5

Probability of picking a card having value more than 5 = 5/10 = 1/2

card with an even number on it = 6, 6, 4, 2, 8, 2

total cards with an even number on it = 6

Probability of picking a card with an even number on it = 6/10 = 3/5

Answered by avinashbeeraka
43

Answer:

1/2 or 0.5 and 3/5 or 0.6

Step-by-step explanation:

According to the question the outcomes are 6, 5, 3, 9, 7, 6, 4, 2, 8, 2.

So, the total number of outcomes are = 10

Cards having value more than five are 6, 9, 7, 6, 8.

So, the total number of favourable outcomes are = 5

Now, the probability of picking the card having value more than five = 5/10

= 1/2 (or) 0.5

Cards having the value of an even number are 6, 6, 4, 2, 8, 2.

So, the total number offavourable outcomes are = 6

Now, the probability of picking the card hving even number on it = 6/10

= 3/5 (or) 0.6

Therefore, the required probabilities are 0.5 and 0.6 or 1/2 and 3/5.

Hope this helps you!!!

Similar questions