Question

From a distance of 20 metres from its base, the angle of elevation of the top of a pylon is 32°. Find the height of the pylon.

Answer 1

$\Large{\underline{\underline{\bf{Solution :}}}}$

$\rule{200}{1}$

★ Given :

• Angle of elevation = 32°
• Distance from it's base = 20 m

$\rule{200}{1}$

★ To Find :

We have to find the height of the pylon.

$\rule{200}{1}$

We know that,

$\large{\implies{\boxed{\boxed{\sf{Tan\theta = \frac{Perpendicular}{Base}}}}}}$

Where,

Perpendicular (AB) = x

Base (BC) = 20 m

____________________[Put Values]

$\sf{→tan32^{\circ} = \frac{x}{20}} \\ \\ \sf{→x = 20 \times 0.624} \\ \\ \sf{x = 12.48 \: m} \\ \\ \sf{\therefore \: height \: of \: pylon \: is 12.48 \: m}$

Answer 2

≛ Given that :

• Distance from it's base (BC) = 20 m
• Angle of Elevation = 32°
• Height of pylon = ? (Let the perpendicular AB be x)

(For proper explaination refer to the attachment)

$\huge{\boxed{\mathfrak{\underline{\purple{Solution!}}}}}$

As we know that,

$\red{\boxed{\underline{\underline{\green{tanΦ = \frac{perpendiclar}{base} }}}}}$

on putting the values...

➡️ $tan 32° = \frac{x}{20}$

➡️ x = 20 × 0.624 (as tan 32° = 0.624)

➡️ x = 12.48 m ans.

Therefore,

The Height of pylon is 12.48 m.

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