Math, asked by naveenvarsha5, 8 months ago

From a group of 10 women and 8 men, a committee of 3 men and 3 women is to be formed. In how many ways can the committee be formed if two of men refuse to serve together

Answers

Answered by amitnrw
2

Given : a group of 10 women and 8 men

a committee of 3 men and 3 women is to be formed

To Find : Number of  ways  the committee can be formed if two of men refuse to serve together

Solution:

Women = 10

Men = 8

committee of 3 men and 3 women is to be formed  without any restriction:

= ¹⁰C₃.⁸C₃

= 120 * 56

= 6720

committee of 3 men and 3 women is to be formed  when 2 men selected who refused to work together

then 3rd man can be selected in ⁶C₁ = 6 ways

Ways =  ¹⁰C₃.⁶C₁

= 120 * 6

= 720

Number of  ways can the committee be formed if two of men refuse to serve together = 6720 - 720  

= 6000

6000 ways  the committee can be formed if two of men refuse to serve together

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