Question

From a group of 6 men and 4 women we have to form a committee of 5 people. How

many committees are possible if there are to be 3 men and 2 women?​

Answer 1

Answer:

1 is the ryt ans.....

Step-by-step explanation:

if there are to be 3 men nd 2 women possible committees is 1

Answer 2

The possibilities are for the committee are:

( 5 men and 0 women) OR ( 4 men and 1 woman) OR ( 3 men and 2 women)

Now we will determine in how many ways we could arrange each possibility.

( 5 men and 0 women) = 6 × 5 = 30 way

(4 men and 1 woman) = 6 × 4 + 1 × 4 = 24 + 4 = 28 ways

( 3 men and 2 women) = 6 × 3 + 2 × 4 = 18 + 12 = 30 way.

Now we will add all :

$\longrightarrow$ 30 + 28 + 30 = 88 way.

Then, there are 88 ways that we can create a committee of 6 men and 4 women.