Math, asked by dinalchkarjee, 2 months ago

From a group of 8 women and 6 men, a committee consisting of 3 men and 3 women
is to be formed. In how many ways can the committee be formed if two of the men
refuses to serve together?​

Answers

Answered by rjjoshi2004
0

Step-by-step explanation:

1 man refuse to serve together say man A and Women B.

There are three conditions.

1. If man A is selected and B is not selected.

=

7

C

2

×

5

C

3

=210 (1)

2. If women B is selected and A is not selected.

=

7

C

3

×

5

C

2

=350

3. Both are not selected.

=

7

C

3

×

5

C

3

=224

Total Number of ways =784

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