From a group of men and women 15 women leave from it. then, there are 2 men for each women. after this, 45 men leave. then, there are 5 women for each men . find the double of the number of women in the beginning
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Let number of women be w and man be m
According to question :
2(w-15) = m. = 2w - 30 = m {1}
And
(W-15) = 5(m-45)
W-15 = 5m - 225
W + 210 = 5m {2}
Now multiplying {2} by 2
= 2w + 420 = 10m. {2}
Subtracting {1} from {2} we get
450 = 9m
M = 5
Putting m = 5
We get 2w = 80
According to question :
2(w-15) = m. = 2w - 30 = m {1}
And
(W-15) = 5(m-45)
W-15 = 5m - 225
W + 210 = 5m {2}
Now multiplying {2} by 2
= 2w + 420 = 10m. {2}
Subtracting {1} from {2} we get
450 = 9m
M = 5
Putting m = 5
We get 2w = 80
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