Question

From a leak tap, water droplets are constantly falling. It is 11.25 m high. When 1st drop
reaches to ground, 4th drop comes out. If the distance between 2nd and 3rd drop at this
instant is x meter then calculate the value 100x.

Answer 1

Answer:

375

Explanation:

Total Height = 11.25 m

As given, 1st droplet reaches ground when 4th comes out. Therefore, Distance Between each droplet = 11.25/3 (3 heights ie - Between droplet 1 & 2, 2 & 3, 3&4)

Now to find distance between 2nd and 3rd droplet - we need to find difference between H1(Till 2nd droplet) - H2(Till 3rd droplet)

= 11.25/3 *2 - 11.25/3

= 3.75 = x

Now, 100x = 3.75 * 100 = 375 (Ans)

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Thanks......

Answer 2

Given:

From a leak tap, water droplets are constantly falling. It is 11.25 m high. When 1st drop

reaches to ground, 4th drop comes out.

To find:

If the distance between 2nd and 3rd drop at this

instant is x meter then calculate the value 100x.

Calculation:

• We should know that a freely falling body travels distances in the ratio of odd numbers at every second.

• That means that the distance travelled in consecutive seconds will be 1:3:5:7......

So, we have 4 drops and let constant of proportionality be y ;

$\therefore \: 1y + 3y + 5y = 11.25$

$= > \: 9y = 11.25$

$= > \: y = 1.25 \: m$

Now , distance between second drop and third drop is x (as per question):

From diagram , we can say that:

$\therefore \: x = 3y$

$= > \: x = 3 \times 1.25$

$= > \: x = 3 .75 \: m$

$= > \: 100x = 375 \: m$

So, value of 100x is 375 m.

HOPE IT HELPS.