From a log 11 m long, two pieces of length 23/5 m and 33/10 m are cut off. What is the
length of the remaining log?
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Step-by-step explanation:
the length of the remaining log is 31/10
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The length of the remaining log is 3 1⁄10 m .
Given :
Length of the log = 11m
Length of the pieces which were cut = 23/5 m and 33/10 m
To find :
The length of the remaining log
Solution :
Total length of log that were cut = (23/5 + 33/10) m
= (23*2 + 33*1)/10
= ( 46 + 33)/10
= 79/10
= 7.9 m
= 7 9⁄10 m
Hence, length of the remaining log = Total length of log - length of log that has been cut = 11 - 79/10
= (10*11 - 79*1) /10
= (110 - 79)/10
= 31/10
= 3 1⁄10
Hence, the length of the remaining log is 3 1⁄10 m .
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