From a number of apple,a man sells half the number of existing apples plus 1 to the first customer,sells one -third of the remaining apples plus 1 to the second customer and one-fifth of the remaining apples plus 1 to the third customer.he finds that he has 3 apples left.how many apples did he have originally?
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Step-by-step explanation:
Given From a number of apple,a man sells half the number of existing apples plus 1 to the first customer,sells one -third of the remaining apples plus 1 to the second customer and one-fifth of the remaining apples plus 1 to the third customer.he finds that he has 3 apples left.how many apples did he have originally?
- Let the total number of apples be a
- Now apples sold to first customer will be (a/2 + 1)
- Now remaining will be a – (a/2 + 1)
- = (a / 2 – 1)
- Now apples sold to second customer will be 1/3 of remaining apples plus 1
- = 1/3 (a/2 – 1) + 1
- = a/6 – 1/3 + 1
- = (a/6 + 2/3)
- Now the remaining apples will be a/2 – 1 – (a/6 + 2/3)
- = a/2 – 1 – a/6 – 2/3
- = a/3 – 5/3
- Now apples sold to the third customer will be 1/5 (a/3 – 5/3) + 1
- = a / 15 – 5/15 + 1
- = a / 15 – 1/3 + 1
- = a / 15 + 2/3
- Remaining apples will be a/3 – 5/3 – a/15 – 2/3
- = 5a – 25 – a – 10 / 15
- = 4a – 35 / 15
- According to the question 3 apples are left
- So we get 4a – 35 / 15 = 3
- 4a – 35 = 45
- 4a = 80
- Or a = 80 / 4
- Or a = 20
- So total number of apples he originally had is 20
Reference link will be
https://brainly.in/question/11381952
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