Question

From a number of mangoes, a man sells half the number of existing mangoes plus 1
to the first customer/ then sells (1/3)rd of the remaining number of mangoes plus 1 to
the second customer, than (1/4)th of the remaining number of mangoes plus 1 to
third customer and (1/5)th of the remaining number of mangoes plus 1 to the fourth
customer. He then finds that he does not have any mango left. How many mangoes
did he have originally ?

Answer 1

Answer:

Step-by-step explanation:

Let the No. of mangoes that the man had originally = X

No. of mangoes sold balance

1st customer = (X/2) + 1 (X - 2)/2

2nd customer = (X - 2)/6 + 1 (X - 5)/3

3rd customer = (X - 5)/12 + 1 (X - 9)/4

4th customer = (X - 9)/20 + 1 0

(X - 9)/20 + 1= (X - 9)/4 => X = 14