Question

From a pack of 52 cards, four cards are drawn. Find the chance that they will be the four honours of the same suit?

Answer 1

P(E) =4/52
=1/13
Hope this helps for you

Answer 2

Answer:

$P=\frac{143}{54145}$

Step-by-step explanation:

Here n= Total no. of ways $n=^{52}\textrm{C}_4$

$n=\frac{52\times51\times50\times49}{1\times2\times3\times4}$

$n=13\times17\times25\times49$

$n=270725$

There are four honours (ace,king,queen and knave)in each suit and so there are 4 sets of 4 honours each.  

To obtain the m =favourable number of ways, we have to select one suit of four honours from these four sets.  

$m=^{13}\textrm{C}_4$

$m=\frac{13\times12\times11\times10}{1\times2\times3\times4}$

$m=13\times11\times10$

$m=715$

Probability= No. of favourable outcomes / Total no. of outcomes

$P=\frac{715}{270725}=\frac{143}{54145}$