Question

From a pack of 52 playing cards, 4 cards are removed at random. in how many ways can the 1stplace and 3rd place cards be drawn out such that both are black

Answer 1

There are 26 black cards to choose from on the first draw.
Now the second card can either be black or red.

If black, then there are 25 to choose from, and then for
the third card there will then be 24 black cards to choose
from.

If red, then there are 26 reds to choose from, and then
for the third card there are then 25 black cards to
choose from.

In either case, there are 49 cards left to from on the
4th draw.

So the number of ways we can do this is

26*(25*24 + 26*25)*49 = 1,592,500,

so option 4 is correct.