Question

from a pack of 52 playing cards jacks queen kings and aces of red coloure are removed . from the remaining a card is drawn at random . find probability that the the card drawn is (i ) a black jack , (ii) a red card (iii) a black jack (iv) a picture card ( jacks , queen, and kings , are picture card ) .

plzzz solve this .....

Answer 1

Total no of red cards in the deck are 26.
There are two red Jack Queen King and Ace each .Total no of card removed = 8
Total card remaining is = 52-8 =44.

1.) A black jack = 2/44 = 1/22.(There are two black jack in a deck).
2.)A red card = 18/44= 9/22.( There are 18 red cards remaining as 8 red cards are removed).
3.)A picture card = 6/44= 3/22.(There are 6 black picture cards and 6 red picture cards since the red picture cards are removed.)

Hope this helps.

Answer 2

Answer:

Total number of outcomes = 52

Cards removed = 2+2+2+2 = 8[2 jack, 2 queen, 2 king and 2 aces of red colour]

Remaining number of cards = 52 – 8=44

Total number of outcomes = 44

(i) Favourable outcomes = 2 [There are 2 black queen]

Required probability =

(ii) Favourable outcomes = number of red cards left = 26 – 8=18

Probability for a red card =

(iii) Favourable outcomes = Number of black jacks = 2

Required probability =

(iv) Number of picture cards left =2+2+2 = 6 [jack, queen, King are picture cards]

Required probability =

(v) Honorable cards [ace, jack, queen and king]

No. of honorable cards left = 2+2+2+2=8

Required probability =