From a point ,10 cm away from the centre of a circle a tangent PT of length 8 cm is drawn . Find the radius vof a circle.
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Let O be the centre of the given circle and let P be a point such that OP = 10 cm.
length of tangent PT is 8 cm
the radius is OT be r
tangent make 90° at point of contact with the radius
we get a right angle triangle OPT
by using Pythagoras theorem
(op)2= (pt)2+(r)2
(10)2= (8)2+ (r)2
(r)2= 100-64
r= root(36)
r= 6
therefore the radius of circle is 6 cm
hope you get your answer
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