from a point 100m above a lake the angle of elevation of the stationary helicopter is 30degree and the angle of depression of reflection of the helicopter above the lake is 60 degree find the height of the helicopter above the lake
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Answer: Here's your answer in the image below.
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dhruvbadaya1:
Consequents=Opposite Side that is same
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This is the diagram.
........
Let CF=(h-x)m.
Hence,CD=(100+CF) m. (Since,BA=FD)
BA=100 m(Given)
BA=FD
=>h=(100+CF) m.
In ∆BAD,
tan60°=BA/DA
=>√3 = 100/DA
Hence,DA=100/√3 m.
Hence,x=100√3 m.
Now,In ∆CFB,
tan30°=CF/FB = 1/√3.
=CF/x=1/√3
Hence,CF = x/√3
x=100√3 m
=>CF=100 m.
Therefore,total height is 100+100 = 200 m.
...
Please mark my answer as brainliest.
........
Let CF=(h-x)m.
Hence,CD=(100+CF) m. (Since,BA=FD)
BA=100 m(Given)
BA=FD
=>h=(100+CF) m.
In ∆BAD,
tan60°=BA/DA
=>√3 = 100/DA
Hence,DA=100/√3 m.
Hence,x=100√3 m.
Now,In ∆CFB,
tan30°=CF/FB = 1/√3.
=CF/x=1/√3
Hence,CF = x/√3
x=100√3 m
=>CF=100 m.
Therefore,total height is 100+100 = 200 m.
...
Please mark my answer as brainliest.
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