Question

From a point 375 meters away from the foot of a tower, the top of the tower is observed at an angle of elevation of 45°, then the height (in meters) of the tower is? ...​

Answer 1

Step-by-step explanation:

Let AB be the cliff with AB=300 m

Let DE be the tower with height h

Let BE=x m

In right angles △ABE,

BE

AB

=tan45

0

⇒

x

300

=1

⇒x=300 m

In right angled △ACD

CD

AC

=tan30

0

⇒

x

300−h

=

3

1

⇒

300

300−h

=

3

1

⇒300

3

−

3

h=300

⇒h=

3

300(

3

−1)

⇒h=100

3

(

3

−1)m

⇒h=100(3−

3

) m

Answer 2

Step-by-step explanation:

tan 45° = x/ 375

1 = x/ 375

x = 375m