From a point 50 m away from the base of a multistoreyed building, the angle of elevation of the first floor is found to be 30 and the angle of elevation of the fifteenth floor is found to be 60. What is the distance between the first floor and the fifteenth floor ?
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Answer:
AB - multistoryed building
C - first floor
A - 15th floor
Required distance = AC
In triangle BOC,
tan 30 = BC/OB
1/root 3 = BC/ 50
BC = 50 / root3
In triangle AOB,
tan 60 = AB/OB
root 3 = (BC + AC) / 50
Now, in the above equation, put the value of BC to get the required distance AC.
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