Question

From a point 5m high on a level ground the angle of elevation of atop of electric pole at a distance of 15m from the foot of the pole is 45 degree Find the height of the pole ​

Answer 1

*Refer to the attachment

Let, AD be the height of the point of elevation above the ground. Let AB be the distance of the point from the electric pole.

Given, AD = BE = 5m

AB = DE = 15m

In ∆ABC, B is right angled

tan45° = BC/AB

=> 1 = BC/15

=> BC = 15m

So, the height of the pole = CE

we can write CE as,

CE = BC + BE

CE = 15m + 5m

CE = 20m

∴ The height of the pole = 20m